http://wiki.bash-hackers.org/commands/builtin/read
IFS=', ' read -r -a array <<< "$string"
Note that the characters in
$IFS are treated individually as separators so that in this case fields may be separated by either a comma or a space rather than the sequence of the two characters. Interestingly though, empty fields aren't created when comma-space appears in the input because the space is treated specially.
To access an individual element:
echo "${array[0]}"
To iterate over the elements:
for element in "${array[@]}"
do
echo "$element"
done
To get both the index and the value:
for index in "${!array[@]}"
do
echo "$index ${array[index]}"
done
The last example is useful because Bash arrays are sparse. In other words, you can delete an element or add an element and then the indices are not contiguous.
unset "array[1]"
array[42]=Earth
To get the number of elements in an array:
echo "${#array[@]}"
As mentioned above, arrays can be sparse so you shouldn't use the length to get the last element. Here's how you can in Bash 4.2 and later:
echo "${array[-1]}"
in any version of Bash (from somewhere after 2.05b):
echo "${array[@]: -1:1}"
Larger negative offsets select farther from the end of the array. Note the space before the minus sign in the older form. It is required.
There was a solution involving setting Internal_field_separator (IFS) to
;. I am not sure what happened with that answer, how do you reset IFS back to default?
RE:
IFS solution, I tried this and it works, I keep the old IFS and then restore it:IN="bla@some.com;john@home.com"
OIFS=$IFS
IFS=';'
mails2=$IN
for x in $mails2
do
echo "> [$x]"
done
IFS=$OIFS
BTW, when I tried
mails2=($IN)
I only got the first string when printing it in loop, without brackets around
$IN it works.